a small object is released from rest and falls 1.00 * 10^2 feet near the surface...
a small object is released from rest and falls 1.00 * 10^2 feet near the surface of the earth. neglect air resistance. how long will it take to fall through the 1.00 * 10^2 feet mentioned?
a) 4.5 s
b) 10 s
c) 2.49 s
d) 3.12 s
e) 6.25 s
Homework Answers
ANS c) 2.49 s
Since 100 feet = 30.48 m
Applying equation s = ut + 1/2 at2
30.48 = 0 + 1/2 *(9.8 * t^2)
t^2 = 30.48 / 4.9 = 6.22
t = 2.49 s
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