Question

How much heat does it take to turn 1g of O'C ice into 1g of 0°C water? 2256 J/kg 4.19 kg 3337 J/kg

Answer 1

Part A.

Energy required to phase change is given by:

Q = m*Lf

m = mass of water = 1 gm = 1*10^-3 kg

Lf = Latent heat of fusion = 3.337*10^5 J/kg

So,

Q = 1*10^-3 kg*(3.337*10^5 J/kg)

Q = 3.337*10^2 J = 333.7 J

Correct option is C. (See that SI unit of heat is J and not J/kg, So that must be a typo error)

2.

Increase in Volume of due to change in temperature is given by:

dV = V0*$\beta$*dT

Here, $\beta$ = Volumetric expansion coefficient of aluminum = 70*10^-6 /C (Again in the question there is typing error, as we know that $\beta$ = 3$\alpha$, So it is 100% 10^-6 and 10^9)

Now dT = change in temperature = 575 C

So,

dV = V0*70*10^-6*575

dV = V0*0.04025

dV/V0 = 0.04025

In percentage terms

dV/V0 = 4.025%

Volumetric change of the cube is 4.025%

Let me know if you've any query.