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The specific heat of water is 4186 J/kg C. How much does the internal energy of 300 grams of water change as it is heated fro

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Answer #1

Here,

change in temperature, del T = 46 - 23 = 23 degree C

for the total change in internal energy

change in internal energy = mass * S * delta T

change in internal energy = 0.300 * 4186 * (46 - 23)

change in internal energy = 28883 J

the change in internal energy is 28883 J

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