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a 24.0 kg sample of water is at 10 C. how much heat is needed for it to reach 90 degrees C (the specific heat for water is 4186J/kg C

:) A 24.0 kg sample of water is at 10° C. How much heat is needed for it to reach 90°C? (The specific heat for water is 4186
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Answer #1

Gieen: mass 24 tg = t1=10°C f2=90°c Specific heaf.=c=4186J/koic = 4. 186 kJ ot Heat grequisred = 24x4. |&6X (g0-10) 24x4.186X

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