a 24.0 kg sample of water is at 10 C. how much heat is needed for...
How much heat is required to boil away 1.10 kg of water that is initially at 100 degree C? Latent heat 22.6 times 10^5 J/Kg, specific heat 4186 J/(Kg degree C). a) 2.49 times 10^3 KJ b) 3.49 times 10^6 J c) -2.49 times 10^6 J d) -3.49 times 10^3 KJ
The specific heat of water is 4186 J/kg C. How much does the internal energy of 300 grams of water change as it is heated from 23 to 46 degrees C? Assume that the volume is constant. Internal energy change = Number Joules
1. How much heat is needed to raise the temperature of 3 kg of water from 20oC to 40oC? Give answer in kJ (1kJ = 1000 J) (round answer to 3 sig fig) 2. How much heat is needed to raise the temperature of 3 kg of ice from -40oC to -20oC? (round answer to 3 sig fig) Specific heat of water: C = 4180 J/kgK Specific heat of ice: C = 2090 J/kgK Specific heat of ethanol: C= 2440...
The energy needed to convert 2 kg of ice at -10 °C to water at 10 °C will be { Constants Given: Specific Heat of Water = 4186 J/kg ºc, Specific Heat of Ice = 2100 J/kg ºc, and Latent Heat of Fusion = 3.33 x 105 J/kg. }
1. How much heat energy is required to change a 0.50-kg of ice at – 10 0C to steam at 110 0C? [Lf = 3.33 x 105 J/kg, c ice = 2090, c water = 4186 J/kg.0C, Lv = 2.26 x 106 J/kg, c steam = 2010 J/kg.0C]
How much heat is required to change 456 g of ice at -20.0Degree C into water at 25.0Degree C? specific heat of water = 4186]/(kg-K); specific heat of ice = 2090 J/(kg.K) and latent heat of fusion of water = 33.5 times 10^4 J/kg.
15. How much heat is needed to melt a 4 kg block of cheddar cheese initially at room temperature of 25 degrees C? (assume the melting point of cheddar cheese is 150 degrees C, the latent heat of fusion of cheese is 124 KJ/kg and the specific heat of cheddar cheese is 2.08 KJ/kg C) (in J)
How much heat must be removed from 456 g of water at 25.0 degree C to change it into ice at -10.0 degree C? The specific heat of ice is 2090 J/kg K. the latent heat of fusion of water is 33.5 times 10^4 J/Kg, and the specific heat of water is 4186 J/kg K.
How much heat (in joules) is required to raise the temperature of 34.0 kg of water from 24 ∘C to 89 ∘C? The specific heat of water is 4186 J/kg⋅C∘. Express your answer using two significant figures.
How much heat energy in joules must be added to 78 grams of water initially at 23 degrees Celsius if it ends up at 53 degrees Celsius. Remember that the specific heat capacity of water = 4186 J/ (kg oC) or 1 calorie / (g oC)