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1. How much heat energy is required to change a 0.50-kg of ice at – 10...

1. How much heat energy is required to change a 0.50-kg of ice at – 10 0C to steam at 110 0C?                                                                 

[Lf = 3.33 x 105 J/kg, c ice = 2090, c water = 4186 J/kg.0C, Lv = 2.26 x 106 J/kg, c steam = 2010 J/kg.0C]

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Answer #1

flow charte Oi, o 02 03 o Waten IN°c water -10 i -10 ice 0°C ito 100°c Vater 110°c Napol 30= mcicael It - Tin) = (0.5) X 2090

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