Question

Problem 7.41 12 of 15 > Constants Part A A 144-g basebal moving 26 m/s strikes a stationary 5.25-kg brick testing on small rollers so it moves without significant friction. After hitting the brick, the baseball bounces straight back, and the brick moves forward at 1.14 m/s. Determine the baseball's speed after the colision Express your answer to three significant figures and include the appropriate units. HA 2 Value Units - Submit Request Answer Part B Determine the total kinetic energy before the collision Express your answer to two significant figures and include the appropriate units.

Answer 1

Given: mass of the baseball is mi= 0.144kg speed of the baseball is ui= 26 m/s mass of the brick m₂ = 5.25kg speed of the brick Uq=0 speed of the brick after collision V₂ = 114 m/s. from law of conservation of momentum:. mau, + m242 = miv,+ M2V2 (0.14 4kg)(26m\s) + (5:25 kg)(0)= (0-144kg) (V1)+(5:25kg) (1.14m|s). ME - 15-59 mls. Total kinetic energy before collision :- ½ m, u²t ₂ me u, ². K, = ½ (0.144kg) (26m/s)²+ K,= Iki= 48.672 J Total kinetic energy of ter collision:- Ke = 1.10.14484) (-15.59m|s7+Y(5.25Kg)(1-14)”ns. + Ika 20.87 J