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2. How much force must be added/subtracted from the ( 7 )-kip force at C so that the vertical displacement at C is zero. E =

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solution: - 4 Ey * Ex f २२ AD=DC Rin2 |3in² 3in2 A 3 in 2 o = 452 Smo=cose 42 Let By yft So zin? eft AB eft 7K By F be the foJont B ANBO EHTNBC NAB Zv=o By = 14K > NBD + By zo NBD =-14k [H0 NBC=NAB NBC =-7k Jant a NEC NED NBC 207 Nap=782k Hea NCD cosJomt A UAD A UAB sv=0 UADSmoo UAD=0 EH=0 UAD +UAD Coso =0 7 UAB - Jont B YBD UBC Ev=o By=0 > UBDtBy EH=0 7 UB C=UAB UB czo 7

The value of F came out 7 kips which was already provided at C. Therefore we have not to increase or decrease this force.

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