Question

When a mixture of 13.0 g of acetylene (C2H2) and 13.0 g of oxygen (O2) is ignited, the resultant combustion reaction produces CO2 and H20. The unbalanced equation for this reaction is shown below. C2H2 + O2 CO2 + H2O

Answer 1

Alsun (6) Balance the reaction :- a C2 H₂ +bo2 c Co2 + d H2O a, b, c. and O2 CO2 CO2 and are. H2o coefficient of Ca H2i respectively. 2 C2H2 + 502 - 4 co2 + 2 H2o. a=2 ; b=5 ; c = 4 d = 2 Species co-efficient Ca Ha co2 H2O 2. (b). Find Limiting Reagert. of CzH2 Meall2 and ore mas and O2 respectively com) Mc2H2 = 13 gm (given) moz 138m (given) MC2H2 and Moz are Molecular weight of C2 H₂ and O2 respeehels (gm mole).

MC2 H2 = 26 goly mole. Moz 32 Gml mele N C2 H2 o and C2 H2 No2 are number number of moles and Nc2H2 = MC2H2 MC2H2 = N C2 H2 = I 13 96 No2 = = noz moe Moz 13 32 and 0.40625 II) Асан, Ao₂ mole equivaley in AC2H2 = Mc2 H2 o.5 - AC2H2 = Ao2= noz = 0.40 625 - Ao2 = 0.08125 e . Ao2<AC2H2 Therefore; Op is the limiting Reagent. Antoer

Answers :

(a) 2,5,4,2

(b) Oxygen is limiting reagent

Thank you.