step by step please. A ductile hot rolled steel bar has minimum yield strength of 360...
1. A ductile hot rolled steel bar has minimum yield strength of 360 MPa. Using the distortion-energy and maximum-shear-stress theories, determine the factors of safety for the following plane stress states: (20 points) (a) Ox = 200 MPa, y = 120 MPa (b) x = 180 MPa, Txy = 150 MPa (c) Txy = 100 MPa
A ductile hot-rolled steel bar has a minimum yield strength in tension and compression of Syt = 60 kpsi and Syc = 75 kpsi. Using the ductile Coulomb-Mohr theory, determine the factor of safety for the states of plane stress. 0x = -21.8 kpsi, oy" -21.8 kpsi, and Txy=-16 kpsi The factor of safety is 2.455
A) A ductile hot-rolled steel bar has yield strength in tension and compression of 400 MPa Define Maximum shear stress, and Maximum normal stress for the following stress distribution: ?,-200 Mpa and ?,-200 Mpa, and Txysl 00 Mpa (All the other stresses are set to zero). safety factor using distortion energy theory, Maximum Normal stress theory, and maximum shear stress theory B) For the above material and stress distribution, what is the
Draw the not-yielding envelope of MSS and DE theory, and then
show all the load lines. Please show the yield strength data in
your graph along with other data. You need to use free-hand-sketch
to draw the DE based envelope.
A ductile hot-rolled steel bar has a minimum yield strength in tension and compression of 350 MPa Using the distortion-energy and maximum-shear-stress theories determine the factors of safety for the following plane stress states (a) 100 MPa, a, = 100...
A hot-rolled steel has a yield strength of Syt = Syc = 100 kpsi and a true strain at fracture of & = 0.55. Calculate the factor of safety (n) for the following stress states by using both MSS and DE theory: (a) Ox = -50 kpsi, oy = -50 kpsi, Txy = -30 kpsi (b) Ox = -50 kpsi, Oy = 0 kpsi, Txy = -30 kpsi (c) Ox = 0 kpsi, oy = 50 kpsi, Txy = 30...
Due 10/31/2019 A ductile steel has a yield strength of 40 ksi. Find the factor of safety corresponding to failure by the maximum normal stress theory, the maximum shear stress theory and the distortion energy for each of the following stress states: 1) (a) o, 10 ksi, o, -4 ksi (b) o, 10 ksi, ty 4 ksi (c) o, -2 ksi, o,= -8 ksi, .ay = 4 ksi23
An AISI steel has a yield strength, Sy = 300 Mpa. Plot the failure locus and the load line in the attached diagram. Given that - OA Ox = 210 MPa, Oy = 160 MPa, and Txy -45 MPa Distortion Energy (Von Mise) S Hint: Maximum Shear Stress Oxt Oy OB ОА, Ов + + tzy Failure Theory Diagram 1.jpg Instructions: Download the image (Failure Theory Diagram 1.jpg), complete the d
An aluminum bar has a minimum yield strength in tension and compression of 420 MPa and e = 15%. Find the factor of safety for failure by yielding if: 2. a. b· c. d· ơ,-180 MPa, Oy-180 MPa Ox = 180 MPa, Tyx-180 MPa σ,--80 MPa, Tyx = 120 MPa Tyx=120MPa
Stress Analysis
3. A 20-mm diameter rod made ofa ductile material with a yield strength of 350 MPa is subjected to torque of 100 N.m and a bending moment of 150 N.m. An axial force is then gradually applied. Determine the value of force when the rod begins to yield. Solve the problem two ways using the (a) Tresca theory (Maximum shearing stress theory) and (b) von Mises theory (Maximum distortion energy theory) [12+12 points
3. A 20-mm diameter rod...
2. The bar in the figure is made of steel and is atiched to the wall at the base. neglecting any stress concentrations find the following: The location and value for the maximum stress in the bar. The minimum yield strength that would be required of the material to have a factor of safety of 1.15 using distortion energy and maximum shear stress theory. a. b. 200 mm mm round 250 mm 100 mm 1000 N