Question

A tank (3mx3mx3m) is filled with liquid. Find the center of pressure of the liquid on the vertical side of the tank. Select one: O A. 2.4 m B. 3 m O C. 2.5m D. 2.8m O E.2 m

Answer 1

Centre of Pressure of the liquid on the vertical side of the tank ( measuring from the surface of liquid) = $I_{G}/A\bar{h} + \bar{h}$

Where,

I_{​​​​​​G}=Moment of Inertia of area about an axis passing through the Centre of Gravity of the area and parallel to the free surface of the liquid

A= Area of surface

$\bar{h}$=Distance of Centre of Gravity of the area of the vertical surface from free surface of the liquid

Hence,

$I_{G}$= (3*3^{​​​​​​3})/12=6.75

$\bar{h}$=3/2=1.5

h^*=(6.75/(9*1.5))+1.5=2 m

Option E is correct. i. e. 2 m from the surface of liquid.