Question

QUESTION 3 The circle of radius 4 centered at the point (9,-2, 1) and lying in a plane perpendicular to the x-axis has equation OA Ou (z - 1)2 + (9-0)2 = 42, z = -10 Ос 3)+()= 4?, x=9 0° (y + 2)2 + (z - 1)2 = 4*, x = 9 05. (y + 2)2 + (z – 1)2 = 4, y +z = -10

Answer 1

Answer:

• 4th Option

Solution:

Step 1. In three dimensional co-ordiante system, the plane prependicular to x axis can be written as x = a. Hence, the plane containing the circle centered at (9, -2, 1) is in the plane x = 9.

Step 2. So, in the plane x = 9, circle with radius r = 4 and center (x₀ = 9, y_o = -2, z₀ = 1) is,

(y - y₀)² + (z - z₀)² = r²

(y - (-2))² + (z - 1)² = 4²

(y + 2)² + (z - 1)² = 4²

Step 3. Therefore, 4th Option is correct.