Question

Le mass OL the Dox and the normal force exerted On IL DY the inclined surface. A free body diagram is essential. (5) SOP 6. Calculate the tensions in cables AB, AC and AD required to support the 15 N flowerpot. Draw a suitable free-body diagram (7) Type to search

Just q6 please asap

Answer 1

6m TAB Trg kry 4m E sing ITAD TAB Cosy 3 TAD COMO TAC em Tacling TAC cosa I5N at point A Let TAB, TAD , and Tae be the tensions in cables AB, AD and AC respectively let LEAB=4 , LFAC = 0, LFAD=0 Now, Vector campo components of TAD about de and yaxes are - TAB sine and TAD COSO and vector components of Tae at point A about hand Yaxes are the link and Tac cos & and vector components of at Y and Z axes are - TABCOS Y and TAB ring where negative sign for opposite direction of TAB point A about axes.

Then focom free: body diagram we have TAB sin q = 150 fo and TAB COS Y = TAD Coso + TAC Cose and Tae sing = TAD rino Now from right angle the angle AEAB sin y EB 6 AB 6+ 3r 315 Gillis cos4= EA 3 315 N5 2 AFD AD AF AD 120 25 2 25 In triangle AAFD, LF=900 ring 12444 coso = In triangl A AFC, LF =90° sind E- coso 21 then equation 10, 9 k ③ become. CF Ae 215 AF Але 25 2 15

TAB 2 V5 15 2 TAB= 1555 2 and TAB. 1/3 = TAD 2 TAD A + TAC 3 - TAB 2 TAD + 2 ATAE > 1515 2 TAD + 2 Tae - 7 1585 155 TAS+TAC 15,5 - TAD + TAC 5 4 and we have TAC = TADI -6) - TAC = TAD then from 5 and 6 155 TADA TAD 4 + 2 TAD 7 TAD = 1555 1515 TAC = TAD 1555 N and TART 1. Tensions in cables AB, Ae and AD are 15 EN 1385 and 1585 1585 4 8 2