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3. [18.76/25 Points] DETAILS PREVIOUS ANSWERS ILLOWSKYINTROSTAT1 10.HW.102. MY NOTES ASK YOUR TEACHER PRACTICE ANOTHER A rece

Please help me with d, e, and f. Thanks

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Answer #1

(d)

n1 = 12328

\hat{p}1 = 2058/12328 = 0.1669

n2 = 2441

\hat{p}2 = 324/2441 =0.1327

So,

\hat{p}1-\hat{p}2=0.1669 - 0.1327=0.0342

Pooled proportion is given by:

\bar{p}=\frac{2058+324}{12328+2441}=0.1613

SE=\sqrt{0.1613\times (1-0.1613)\times (1/12328+1/2441)}=0.008149

So,

Distribution to use :

Normal

with mean = \mu = 0.0342

and SD = 0.0081

So,

Answer is:

p1 - p2 = N (0.0342, 0.0081)

(e)

Test Statistic is given by:

Z=\frac{0.0342}{0.0081}=4.20

So,

Test Statistic is:

Z = 4.20

(f)

By Technology,

p - value = 0.0000

Correct option:

If H0 is true, then there is a chance equal to the p value that the difference in the proportion of Hispanic students of the public university and the proportion of Hispanic students at the community college is at least 0.03.

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