A chemistry teacher needs to make 2.30 L of a potassium chloride solution for an experimen...

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A chemistry teacher needs to make 2.30 L of a potassium chloride solution for an experimen The concentration of the required

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Answer 1

Answer #1

1. Given data:

M = 3.10 M

V = 2.30 L

Molar mass of KCl = (39 + 35.5 ) g/mol = 74.5 g/mol

Molarity (M) = no. of moles of solute (n) / volume of solution V in litre ------- (1)

no. of moles (n) = given mass / Molar mass --------(2)

Using equation (2) in equation (1)

M = (given mass / molar mass ) / V

3.10 = (given mass / 74.5) / 2.30

given mass = 531.18 g of KCl

Correct option is third (532 g).

2. H₂O (l) + H₂O (l) $\rightarrow$ H₃O⁺ (aq) + OH^- (aq)

K = [H₃O⁺ (aq)] [OH^- (aq)] / [H₂O (l)] [H₂O (l)]

Concentration of water is taken as 1 as it is in pure liquid form and in huge amount.

K_w = [H₃O⁺ (aq)] [OH^- (aq)] = 1.00 x 10^-14

Correct option is third.

3. Gases are easily compressible as molecules have great distances between each other and due to which they can be stored under high pressure and a small container can contain large volume of gas.

Correct option is fourth (gases are compressible).

4. K_w = [H⁺] [OH^-] = 10^-14

[H⁺] = 10^-14 / [OH^-]

= 10^-14 / 7.95 x 10^-6

= 0.126 x 10^-8 = 1.26 x 10^-9 M

Correct option is first (1.26 x 10^-9 M) .

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Answer 2

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