Question

Ca(OH)₂ (aq) + 2HCl (aq) CaCl₂ (aq) + H2​O (l)

An aqueous solution of Ca(OH)₂with a concentration of 0.161 M was used to titrate 25.00 mL of aqueous HCl. 18.63 mL of the Ca(OH)₂was required to reach the endpoint of the titration. An aqueous solution of Ca(OH)₂with a concentration of 0.161 M was used to titrate 25.00 mL of aqueous HCl. 18.63 mL of the Ca(OH)₂was required to reach the endpoint of the titration.

A) How many moles of base were required to react completely with the acid in this reaction?

B) How many moles of HCl were present in the original 25.00 mL of acid?

C) What is the molarity of the original HCl solution?

Answer 1

• The Reention de carolul cuita Huis . as follow Cacom), Car) + 2 Hulor) Call 696) + 4,011) Miu a MUL Mic molarity of Calou (0.161m) vir volume at La Coll (18.63 mis ! na no.de moles of CaCOH)₂ (amol) Ma nolarity of HU ? - volume of HU (25.00mL) - Mg = no. at moles of HU (2001) a (A) moles de Base CaCOH), a 18.63 mL x x 0.161 mol =10.00300 mol calolla (000mL L . mola ad Hu presented an solul. amol Hu . 0:00 300 mol caCollux imol ce cov) -0.0060o mol Hul (c). molarity of Huir molley of Hu molavity- volume dritu (2) = 0.00600 mol 2s0o mex(come) = to.room Heub, indarity a Hua fornom Oth1 MX18.63mCreof I not s 0.2399m Ro.mom

Number of moles = Volume × Molarity

Molarity = number of moles / Volume