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A 0.00100 mol sample of Ca(OH)2 requires 25.00 mL of aqueous HCl for neutralization according to...

A 0.00100 mol sample of Ca(OH)2 requires 25.00 mL of aqueous HCl for neutralization according to the reaction below. What is the concentration of the HCl?
Equation: Ca(OH)2(s)
+ 2HCl(aq) → CaCl2(aq) + H2O(l)

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Answer #1

As per the equation 1 mole of Ca(OH)2 requires 2 moles of HCl

It is given that there are 0.001 moles of Ca(OH)2 in the sample. Therefore, this will require 2* 0.001 = 0.002 moles of HCl

Concentration is given as Molarity = moles of HCl/volume of HCl = 0.002 moles/0.025 L = 0.08M

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