Question

Chewbacca is pushing a 250 kg crate up a ramp, which is 26 degrees above the horizontal, into the Millenium Falcon. He managed to push the crate 11.4 m up the ramp when he spots some enemy bounty hunters. Chewbacca tries to defend himself by shooting at them and the crate starts sliding down the ramp. The coefficient of kinetic friction is 0.45.

What is the work due to kinetic friction on the crate?  

What is the gravitational potential energy of the crate at it's maximum height before it starts sliding down the ramp? (Assume y = 0 m is at the bottom of the ramp.

What is the change in kinetic energy of the crate?  

What is the speed of the crate after it has slid down the ramp and reaches the bottom?  

Answer 1

0 = 260, d=11.4 m., uso.45 m = 250 Rg Work due to kinetic friction Wq = (umgeaso) a 6°)x114 11296-5 I ( Answer = 6.4s x 250 x4.d can 26 = Wf Gravitational GP Potential energy is a sino mg 250 x 9.8 x 11.4 sin 26 - 12 243.7 J o E change in Kinetic AKE energy + GP 2 นป Wy = 11296.5 + 12243.7 . 23540J

After sliding down let velo elocity Then by energy - comerwation Wo 1129615a С РЕ 12243.7 I mu 2 v=2.75 m 2.75 m/s (Answer s