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3) Hypobromous acid (HOBr) is a weak monoprotic acid, with K. = 2.1 x 10 a) What is the value for pH for a 0.0168 M aqueous s

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Given that Molarity of HOBr = 0.0168 M Ka of HOBr = 2.1 x 10-9 pka = -log(2.1 x 10-9) = 8.678 a) Dissociation of HOBr is Ка H

b) Addition of 0.0100 mol of NaOH : Number of moles of HOBr = M*V = 0.0168 M * 1.00 L = 0.0168 mol Number of moles of NaOH =

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