Question

please help with question four and five

3. For the reaction PbCl2 (6) Pb2+ + 2CV, what is the value of the equilibrium constant if [Pb 2+] = 0.0022 M and (CI) is 0.027 M? [P621] = 0.002am kc [Pb2+] [...] [cr] =0.027m [PbCl2 (s) [pbela (s)]= Ke=0.0022x10.02222 4. The equilibrium constant for the reaction of nitrogen and hydrogen to produce ammonia is = 1.6.x10-6 0.094 M? at 450°C. If [N2) =0,012 M and [H2] = 0.42 M at equilibrium, what is (NH3)? S 5. How would an increase in gas pressure affect the reaction PCs () =PC13 (8) + Cl2(g)? 6. For the reaction HCN (9) + H20 (1) = H+ (aq) + CN- (aq) how would decreasing (CN) shift equilibrium? According to Le chatelier principle, decreasing [cn-] Shift the equiliboom in toward 7. For the reaction HCN (g) + H20 (1) =H30 + (aq) + CN (aq) how would adding H307 uilibrium?

Answer 1

It is based on the concept of Chemical equilibrium.It can be done as follows:

to Equilibrium constant of Solution-4) Reaction of nitrogen and hydrogen pouduce ammonia 0.094 M2 at 450°C. (N2] = 0.012 M and [H₂] = 0.42M at Equilibrium [NH3] = ? (To find) Reaction is given as : N2 (g) + 3 H₂ (3) = 2NH3(8) Ke=0.094 It is M²2 Q balanced equation For reaction 6 , is given as - Ke INP3] [Ng1,7 3 2 Where INH3] , [Na], [Hz] are concentration of NH3, Na and Ha nespectively and Equilibrium. At Equilibrium, we know, 2 ke=0.094 m [NH] = ? (To find) [Na] =0.012 M 2 [Mg] = 0.42 M .. Substituting all values in ea. , We get,

ke 0.094 m2 [Nita] ² (0.012)M (6.uz) m3 [NH3]? 3 10.012)x 0.074 m ke 0.094 [NH37² 8.88xiou my M-2 00, [NH3]²= 8.83 x 10-4 x0094 M-2xmi or, [N#37: 0.83472x:0-4 Mt. m2 oo, [Nf3]² = 0.83472x10 m2 Taking 1 Square root we hame. [NM3] = 0.914x102 or, [N+3 ] = 9.14x !03 m is Equilibrium concentration of NH ₃ 9:14 x 103 m [NH 3] = 9.144:03M Ans ns the Solution 5 :- Le-chaterlier's principle govern Effect at Equilibrium q various changes made. Le-chaterlier principle is is given by :-

a change is applied Le-chatelier's principle : If system Equilibrium Will shift in that direction in to the at then &quilibrium which it can minimise the effect Equilibrium effect of change applied and is established again under neur Condition.

On increasing Effect of Press are in pressure Equilibrium will shift in the direction in which pressure decrease ie number of moles in the reaction decreases. Given reaction is :- Pas(g) = PU₃ (9) + Cl (3) It can be written as: - it ich @) IPUs ? 1P03 (9) I Product side Reactant No. of moies=1 No. of moles=2 : Reactant side has less moles then increasing pressure Equilibrium shift in backward direction soe. towards PUS, ;. On increasing in pressure given reaction will shift in backward direction (towards Pus).
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