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The tail rotor section of a Black Hawk helicopter consists of four blades, each has a mass of 2 [kg), and a gear box that wei

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Answer #1

1.

Total mass of the rotor =4*2 +38= 46 kg

2.

Given Natural frequency of tail section=135 rad/sec

\omega_n =\sqrt{\frac{k}{m}} => k= \omega_n^2 *m

K=135^2 *46 = 838.35 kN/m

3.

Given Natural frequency as 135 rad/sec already

4.

Frequency of rotation is w.

\omega=\frac {2*\pi*N}{60} = \frac{2*3.14*850}{60} = 89.01 rad/sec

r=\frac{\omega}{\omega_n}

r is frequency ratio. = 89.01/135 = 0.659

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