Question

The cold-drawn AISI 1040 steel bar shown in the figure is subjected to a completely reversed axial load fluctuating between 28 kN in compression to 28 kN in tension. Estimate the fatigue factor of safety based on achieving infinite life and the yielding factor of safety. If infinite life is not predicted, estimate the number of cycles to failure. 6-mm. 25 mm + 10 mm What is the factor of safety against yielding? The factor of safety against yielding is

Answer 1

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upon Solution - This problem in baxed concept of -machine design. Calculation of Applica stressex at critical sections Maximum load. Minimum Prin = 28 kN (tensile =-28 kw (compressive) meam lead = Presonan Pingat Paris Amplitude load. load Pamp = Pmax- Pris - 28 KN. Pmeen - 0 meam stress neona Area Amplitude stress Camp Pane 28 kW Area A Area A cat critical section = (25mm 6mm) x lomm gomm² Se Ame -a - 2 & KN 147.36 mpa 190 Calculation of endurance strength. - Froom internet property of AISI iono steel bar - ultimate stranth out = 620 MPa Yield strength out = 450 mea

Endurance strength Te e os out = 310 mpa Corrected Edurania strength kb Lot tak kek Je ałachiel) ka Csurface finish factor) = 0.78 (from charta (size factor) = 0.85__( 502 de 375) de = 50.8²bh = 0.8 Joh. be_width = 25mm h = thickness ke ( reliability factor) = 0.897 (lor 90%. Ycliability) stress Conc. factor) = lomm 1 Kf kg = fatique Stress Concentration factor for dero notch seatitirity) 184.36 te = so mpa Tuchor of safety In Yield! by line Yield IN Ty the Ees 7 t Dis felting values

A = 3 * 05 (in yield) - Infatique ! by so derberg theory 4 om ry Putting Ja Tel N values 7 1.25 (in fatique)

Calculation of no. of cycles for component :- are ib Al no. of cydex stress amplitude enduronce strength. taken as infinite is less than of component. 600) Ta < Je cadex of are inlinite. Antwert. @ fos Yield 3.05 1.25 fotique > (9 No. of cyclex infinite