Question

Engineering economy

In fluid flow problems, the flow velocity in a long horizontal pipe depends on the pipe material, pipe geometry and fluid properties in addition to the pump power. For a horizontal pipe with a pump, the friction factor can be obtained from many correlations such as Colebrook-White Equation: 2.100 =-2 logo 5.0452 Re log + 5.8506 (Re)-a) (1) 3.7065 2.4257 In which, fis the friction factor and ris the roughness ratio given by: given by: pDV Where is the roughness of the pipe material and Dis the pipe diameter. Note that riis dimensionless and hence both and D should be expressed in the same units. Reis Reynolds number which can be calculated from: Rea (2) Where pis the fluid density, u is the fluid viscosity. A cast iron pipe that is 14.64 cm in diameter is 3.435 km long (3435 m). It is to convey octane. The estimated friction factor fis 0.023 a. Determine the velocity of the flow using secant method with an accuracy of 0.001%. By first solving for Re in (1) and then obtaining the required velocity in (2). b. In another part of the same code, Manipulate equation (1) to have f = F(Re) and plot f versus Re for the interval 3000 S Re S 500,000 For octane: p=701 kg/m p=0.51x10N.s/m² For cast iron: E=0.025 cm Note: in Python, In(2) is coded log (2) while the logarithm to the base of 10 like log(2) is coded log102) • Make sure all units are consistent. Save your file as s123456.py where 123456 is your student ID.

Answer 1

Saathi Date oploss f ļ py? Giren AP = Gesi = 6 lbf (6) (32.174) Ibm. ft in2 21/144) ft² 32 L= 4ft D 0.1 in = 0.1 ft 12 ft s² 0: P = 62.4 lbmlft3 V = 5 ft/s = 2.034 X10s Ibf. s I ft² => 0 =5 (6) (32.174) Ibn. & = f (4 . (62-4 (1144 12 » f = 0.0742 Reynolds number PYD = 624(106) 5 (Ft 2.034810 Tbf.5 ft2 9) 512 2 0.) 12 cs Scanner CamScanne Page No

1.278 xlos 1 . Ibm. ft s2 I bf (1.278X10 Ibm-ft 1 1 s2 32. 1741bm It s Re = 3972.15 L 4ooo Quansition flow 1 -2 log Reif 12:5) + st ह 3.72D of 2.51 ह + 10.0742 - 269 2972. 15. 10:0742 (372)4 92 0.16 2.51 t E 0.031 (3972:15 30.0742 E = 4:887 X103 ft