Calculate the pH of a 0.051 M solution of sodium acetate(CH3COONa). The Ka for lactic acid is 1.4 x 10-4
pH of salt of strong base and weak acid (CH3COONa) = 7+ 1/2(pKa +log(c))
= 7+1/2(-log(Ka)+log(C))
= 7+1/2(-log(1.4*10^-4)+log(0.051)
= 8.28
Ans: d
Question 14Calculate the pH of a 0.051M solution of sodium acetate (CH3COONa). The Ka for lactic acid is 1.4 × 10-4.a. 12.71b. 2.57c. 1.29d. 8.28e. 11.43
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calculate the number of grams of CH3COONa * 3H2O (sodium acetate tri-hydrate) needed to make 250.0 mL of a CH3COOH (acetic acid)/ CH3COONa * 3H2O buffer. The target pH of the buffer is 5.25. The given concentration of [CH3COOH] is equal to 0.10 M. Ka = 1.80 x 10-5 for acetic acid. PLEASE EXPLAIN :( Q1:Given the Ka value in the instructions (1.80 x 10-5). Calculate the pKa Q2:Use the Henderson-Hasselbalch equation to determine the ratio of [CH3COO-]/[CH3COOH] needed to...
calculate the number of grams of CH3COONa * 3H2O (sodium acetate tri-hydrate) needed to make 250.0 mL of a CH3COOH (acetic acid)/ CH3COONa * 3H2O buffer. The target pH of the buffer is 5.25. The given concentration of [CH3COOH] is equal to 0.10 M. Ka = 1.80 x 10-5 for acetic acid. Use the Henderson-Hasselbalch equation to determine the ratio of [CH3COO-]/[CH3COOH] needed to make the buffer. pH = pKa + log([CH3COO-]/[CH3COOH]) Now calculate the concentration of acetate ion (CH3COO-...
Calculate the pH of a solution made by adding 42 g of sodium acetate, NaCH3COO, to 22 g of acetic acid, CH3COOH, and dissolving in water to make 300. mL of solution. Hint given in feedback. The K, for CH3COOH is 1.8 x 10-5 M. As usual, report pH to 2 decimal places. Answer: Calculate the pH of a solution made by adding 59 g of sodium acetate, NaCH3COO, to 22 g of acetic acid, CH3COOH, and dissolving in water...