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Answer 1

Answer #1

Answer

Solubility of AgCl is 4.63*10^-10M

Explanation

Ksp of AgCl in KCl is 1.0*10^-10

Let us consider the following equation as the representation of AgCl solubility

AgCl $\rightleftharpoons$ Ag⁺ + Cl^-

Let us assume [Ag⁺] = x

At equilibrium conditions, [Ag⁺] = x; [Cl^-] = 0.216+x

Ksp = [Ag⁺][Cl^-] = x*[0.1 + x]

In actual, x<<<0.1; Therefore, the term x in (0.216+x) will be easily neglected to become just 0.216

Therefore, 10^-10 = 0.216x

x = 4.63*10^-10M

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Answer 2

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