Translate the High order language program to assembly language and generate PEP9 assembly language code.
#include <stdio.h> int main() { int number; scanf(“%d”,&number ); if (number <0) { number =- number; } printf ("%d", number); return0; }
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Translate the High order language program to assembly language and generate PEP9 assembly language code. #include...
Translate the following C program to Pep/9 assembly language. #include <stdio.h> int main() { int number; scanf("%d", &number); if (number % 2 == 0) { printf("Even\n"); } else { printf("Odd\n"); } return 0; }
Translate the following C program to Pep/9 assembly language. #include <stdio.h> const int limit = 5; int main() { int number; scanf("%d",&number); while (number < limit){ number++; printf("%d",number); } return 0; }
Hello guys ! Could you let me know about this ?? Translate the following C program to Pep/9 assembly language. #include <stdio.h> int main() { int number; scanf("%d", &number); if (number % 2 == 0) { printf("Even\n") } else { printf("Odd\n"); } return 0; } Thank you !
Translate the following C program to Pep/9 assembly language. It multiplies two integers using a recursive shift-and-add algorithm. mpr stands for multiplier and mcand stands for multiplicand. A recursive integer multiplication algorithm #include <stdio.h> int times(int mpr, int mcand) { if (mpr == 0) { return 0; } else if (mpr % 2 == 1) { return times(mpr / 2, mcand * 2) + mcand; } else { return times(mpr / 2, mcand * 2); } } int main() { ...
ranslate the following C program to Pep/9 assembly language. Note: Your jump table must have exactly four entries, but your program must have only three case symbols and three cases. #include <stdio.h> int main () { int guess; printf(“Pick a number 0..3: “); scanf(“%d”, &guess); switch (guess) { case 0: case 1: (printf (“Too low”); break; case 2: printf(“Right on”); break; case 3: printf(“Too high” ); } printf(“\n”); return 0; }
Can anyone help to solve this MIPS assembly language problem? Please help. Translate the fowlowwing C code to MIPS assembly language. void main() { int i, sum, begin, end; for(i=0; i < 5; i++){ scanf(“%d, %d”, &begin, &end); sum = accum_range(begin, end); printf(“sum[%d: %d] = %d\n”, begin, end, sum); } int accum_range(int a, int b){ return accum (b) - accum(a); } int accum(int final) { int sum = 0; for (int I = 1; I <= final; I = I...
I need the programming to be in language C. I am using a program called Zybook Prompt: Write a statement that outputs variable numObjects. End with a newline. Given: #include <stdio.h> int main(void) { int numObjects; scanf("%d", &numObjects); return 0; } What I did so far. I am not sure if its right tho? #include <stdio.h> int main(void) { int numObjects; scanf("%d", &numObjects); printf(" num Objects is "); printf("%d\n", userAge); return 0; }
Write an assembly language program that corresponds to the following C program: int width; int length; int perim; int main () { scanf ("%d%d", &width, &length); perim = (width + length) * 2; printf ("width = %d\n", width); printf ("length = %d\n\n", width); printf ("perim = %d\n", perim); return 0; }
MIPS assembly language Covert this code to MIPS: #include <stdio.h> int function (int a) int main)i int x=5 ; int y: y function(x); printf "yd",y); return 0; int function (int a) return 3*a+5; Assumptions: . Place arguments in $a0-$a3 . Place return values in $vO-$v1 Return address saved automatically in $ra . lgnore the stack for this example. (Thus, the function will destroy registers used by calling function
In PEP8 code. assembly pep8 code. 30. Write an assembly language program that corresponds to the following C+ program #include <iostream> using namespace std; int num; int main() cin >> num: num = num/ 16; cout << "num = " << num << endl; return 0; 21 de