Can anyone help to solve this MIPS assembly language problem? Please help. Translate the fowlowwing C...
Homework Answers
Actually the code is wrong and herewith providing the right code as follows:
#include<stdio.h>
void main() {
int i, sum, begin, end;
for(i=0;i<5;i++)
{
scanf("%d,%d",&begin, &end);
sum = accum_range(begin,end);
printf("sum[%d:%d]=%d\n",begin,end,sum);
}
}
int accum_range(int a,int b)
{
return accum(b) - accum(a);
}
int accum(int final)
{
int sum=0;
for(int I=1;I<=final;I+1)
sum=sum+I;
return sum;
}
MIPS ASSEMBLY LANGUAGE CODE IS:
.file 1 ""
.section .mdebug.abi32
.previous
.nan legacy
.module fp=32
.module nooddspreg
.abicalls
.section .rodata.str1.4,"aMS",@progbits,1
.align 2
$LC0:
.ascii "%d,%d\000"
.align 2
$LC1:
.ascii "sum[%d:%d]=%d\012\000"
.section .text.startup,"ax",@progbits
.align 2
.globl main
.set nomips16
.set nomicromips
.ent main
.type main, @function
main:
.frame $sp,64,$31 # vars= 8, regs= 6/0, args= 24, gp= 8
.mask 0x801f0000,-4
.fmask 0x00000000,0
.set noreorder
.cpload $25
.set nomacro
addiu $sp,$sp,-64
sw $18,48($sp)
sw $17,44($sp)
lw $18,%got($LC0)($28)
lw $17,%got($LC1)($28)
movz $31,$31,$0
sw $20,56($sp)
sw $19,52($sp)
sw $16,40($sp)
.cprestore 24
sw $31,60($sp)
li $16,5 # 0x5
addiu $20,$sp,36
addiu $19,$sp,32
addiu $18,$18,%lo($LC0)
addiu $17,$17,%lo($LC1)
$L6:
lw $25,%call16(__isoc99_scanf)($28)
.set macro
.set reorder
.end main
.size main, .-main
.text
.align 2
.globl accum_range
.set nomips16
.set nomicromips
.ent accum_range
.type accum_range, @function
accum_range:
.frame $sp,0,$31 # vars= 0, regs= 0/0, args= 0, gp= 0
.mask 0x00000000,0
.fmask 0x00000000,0
.set noreorder
.set nomacro
blez $5,$L13
nop
$L17:
b $L17
nop
$L13:
blez $4,$L15
nop
$L18:
b $L18
nop
$L15:
j $31
move $2,$0
.set macro
.set reorder
.end accum_range
.size accum_range, .-accum_range
.align 2
.globl accum
.set nomips16
.set nomicromips
.ent accum
.type accum, @function
accum:
.frame $sp,0,$31 # vars= 0, regs= 0/0, args= 0, gp= 0
.mask 0x00000000,0
.fmask 0x00000000,0
.set noreorder
.set nomacro
blez $4,$L20
nop
$L22:
b $L22
nop
$L20:
j $31
move $2,$0
.set macro
.set reorder
.end accum
.size accum, .-accum
.ident "GCC: (Ubuntu 5.4.0-6ubuntu1~16.04.9) 5.4.0 20160609"
Add Answer to:
Can anyone help to solve this MIPS assembly language
problem?
Please help.
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