Convert the below C code to basic MIPS. Please leave comments for explanation #include <stdio.h> int main(void) {...
Convert the below C code to basic MIPS. Please leave comments for explanation
#include <stdio.h>
int main(void)
{
printf("Insert two numbers\n");
int a,b;
scanf("%d",&a);
scanf("%d",&b);
a=a<<2;
b=b<<2;
printf("%d&%d\n",a,b);
return 0;
}
Homework Answers
Code in MIPS :
.file 1 ""
.section .mdebug.abi32
.previous
.nan legacy
.module fp=32
.module nooddspreg
.abicalls
.rdata
.align 2
$LC0:
.ascii "Insert two numbers\000"
.align 2
$LC1:
.ascii "%d\000"
.align 2
$LC2:
.ascii "%d&%d\012\000"
.text
.align 2
.globl main
.set nomips16
.set nomicromips
.ent main
.type main, @function
main:
.frame $fp,40,$31 # vars= 8, regs= 2/0, args= 16, gp= 8
.mask 0xc0000000,-4
.fmask 0x00000000,0
.set noreorder
.cpload $25
.set nomacro
addiu $sp,$sp,-40
sw $31,36($sp)
sw $fp,32($sp)
move $fp,$sp
.cprestore 16
movz $31,$31,$0
lw $2,%got($LC0)($28)
nop
addiu $4,$2,%lo($LC0)
lw $2,%call16(puts)($28)
nop
move $25,$2
.reloc 1f,R_MIPS_JALR,puts
1: jalr $25
nop
lw $28,16($fp)
addiu $2,$fp,24
move $5,$2
lw $2,%got($LC1)($28)
nop
addiu $4,$2,%lo($LC1)
lw $2,%call16(__isoc99_scanf)($28)
nop
move $25,$2
.reloc 1f,R_MIPS_JALR,__isoc99_scanf
1: jalr $25
nop
lw $28,16($fp)
addiu $2,$fp,28
move $5,$2
lw $2,%got($LC1)($28)
nop
addiu $4,$2,%lo($LC1)
lw $2,%call16(__isoc99_scanf)($28)
nop
move $25,$2
.reloc 1f,R_MIPS_JALR,__isoc99_scanf
1: jalr $25
nop
lw $28,16($fp)
lw $2,24($fp)
nop
sll $2,$2,2
sw $2,24($fp)
lw $2,28($fp)
nop
sll $2,$2,2
sw $2,28($fp)
lw $2,24($fp)
lw $3,28($fp)
nop
move $6,$3
move $5,$2
lw $2,%got($LC2)($28)
nop
addiu $4,$2,%lo($LC2)
lw $2,%call16(printf)($28)
nop
move $25,$2
.reloc 1f,R_MIPS_JALR,printf
1: jalr $25
nop
lw $28,16($fp)
move $2,$0
move $sp,$fp
lw $31,36($sp)
lw $fp,32($sp)
addiu $sp,$sp,40
j $31
nop
.set macro
.set reorder
.end main
.size main, .-main
.ident "GCC: (Ubuntu 5.4.0-6ubuntu1~16.04.9) 5.4.0 20160609"
images:
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