Convert this C program to Js (Java script) from Visual Studio Code
#include<stdio.h> int main(){ char firstName[100]; char lastName[100]; printf("Enter Your Full Name: \n"); scanf("%s %s", firstName, lastName); printf("First Name: %s\n", firstName); printf("Last Name: %s\n", lastName); return 0; }
var name = prompt("Enter Your Full Name: ");
var firstName = name.split(" ")[0];
var lastName = name.split(" ")[1];
document.write("First Name: " + firstName + "<br />");
document.write("Last Name: " + lastName + "<br />");
Convert this C program to Js (Java script) from Visual Studio Code #include<stdio.h> int main(){ char...
C program help #include #include #include void PrintName(char firstname[16], char lastname[16]); int main () { char firstname[16]; char lastname[16]; printf("please enter your first name:"); scanf("%s",firstname); printf("please enter your last name:"); scanf("%s",lastname); PrintName(firstname,lastname); return 0; } void PrintName(char firstname[16], char lastname[16]){ char fullname[34]; *fullname=*firstname+*lastname; (char*) malloc (sizeof (*fullname)); if (strlen(firstname) > 16||strlen(lastname)>16||strlen(fullname)>16) fflush(stdin); else printf(" the full name is %s %s \n",firstname,lastname); printf(" the full name is-> %s",fullname);/*why is one not run*/ return 0; }
Convert the below C code to basic MIPS. Please leave comments for explanation #include <stdio.h> int main(void) { printf("Insert two numbers\n"); int a,b; scanf("%d",&a); scanf("%d",&b); a=a<<2; b=b<<2; printf("%d&%d\n",a,b); return 0; }
Convert the below C code to basic MIPS. Leave comments for explanation please #include <stdio.h> int main(void) { printf("Insert two numbers\n"); int a,b,c; scanf("%d",&a); scanf("%d",&b); c=a|b; printf("%d|%d=%d\n",a,b,c); return 0; }
Write as a shell script Write as a shell script # include <stdio.h> int main (void) {int area_code, prefix, number; printf("Enter phone number [(999) 999-9999]:"); scanf("(%d)%d-%d", &area_code, & prefix, & number); printf("You entered %d-%d-%d \n", area_code, prefix, number); return 0;}
i need flowchart for the following c code #include <stdio.h> int main() { int n, i, sum = 0; printf("Enter an integer: "); scanf("%d",&n); i = 1; while ( i <=n ) { sum += i; ++i; } printf("Sum = %d",sum); return 0; }
Solve using C programming 3. lf you are given this code. #include <stdio.h> int main() int var1, var2; int sum; printf("Enter number 1:\n "); scanf("%d",&var1); printf("Enter number 2:In ); scanf("%d",&var2); sum-var1+var2; printf ("Vnsum of two entered numbers : %d", //printf ("Output: %d", res); sum); return e; Modify this code by creating a function called "addition". Make the arguments of the functions numberl and number 2. Add the two values in the function. Return a value called "result". Print "result" in...
#include <stdio.h> int main(int argc, char *argv[]) { int i; for (i = argc - 1; i > 0; i--) printf("%s ", argv[i]); printf("\n"); return 0; } can you explain this code in c and why use this function
All in C please~ #1 Consider this program: #include <stdio.h> int main () { /* main */ constint constant1 = 10, constant2 = 20, constant3 = 14; int input_value; char current_truth; printf("What is the input value?\n"); scanf("%d", &input_value); current_truth = input_value > constant1; printf("current_truth = %d\n", current_truth); current_truth = current_truth && (input_value < constant2); printf("current_truth = %d\n", current_truth); current_truth = current_truth && (input_value == constant3); printf("current_truth = %d\n", current_truth); } /* main */ What is the output of this program...
Translate the following C program to Pep/9 assembly language. #include <stdio.h> int main() { int number; scanf("%d", &number); if (number % 2 == 0) { printf("Even\n"); } else { printf("Odd\n"); } return 0; }
#include <stdio.h> #include<string.h> int main() { char strText[100] ="Start"; char i; int nTextASCIISum = strText[0] + strText[1] + strText[2]; int nTextLen = strlen(strText); int count = 0; printf("Welcome to token generator!\n"); printf("Enter a word to use in the token generator.\n You may enter as many words as you like. \n Press q and key when finished.\n"); scanf("%c", &strText[i]); //compute when to stop loop //check nTextLen == 1 and strText[0] == 'q' for(i=0;i< nTextLen;i++) if ((strlen(strText) != 1) || (strText[0] !=...