All in C please~
#1 Consider this program:
#include <stdio.h>
int main () { /* main */
constint constant1 = 10, constant2 = 20,
constant3 = 14;
int input_value;
char current_truth;
printf("What is the input value?\n"); scanf("%d",
&input_value);
current_truth = input_value > constant1; printf("current_truth =
%d\n", current_truth); current_truth =
current_truth && (input_value < constant2); printf("current_truth = %d\n", current_truth); current_truth =
current_truth && (input_value == constant3); printf("current_truth = %d\n", current_truth);
} /* main */
What is the output of this program for the following inputs?
(a) 8
(b) 14
(c) 16
(d) 20
a) current_truth = 0 current_truth = 0 current_truth = 0 b) current_truth = 1 current_truth = 1 current_truth = 1 c) current_truth = 1 current_truth = 1 current_truth = 0 d) current_truth = 1 current_truth = 0 current_truth = 0
All in C please~ #1 Consider this program: #include <stdio.h> int main () { /* main...
6. Consider the following program: #include <stdio.h> main() { int a,b,c,d ; a=0; while (1) { printf("%d\n", a); printf("Input? "); scanf("%d",&c); if (c == 0) break; d=0; for (b=1; b<=c; b++) if (c%b == 0) d++; if (d == 2 11 C == 1) a=a+c; } } What does this program do? Rewrite the code, organizing it using sound principles. Include comments and redo variable names and indentation. Use multiple functions, blocks, and/or preprocessing if you deem it necessary.
Translate the following C program to Pep/9 assembly language. #include <stdio.h> int main() { int number; scanf("%d", &number); if (number % 2 == 0) { printf("Even\n"); } else { printf("Odd\n"); } return 0; }
OPERATING SYSTWM Question 31 What is the output of this C program? #include #include void main() int mptr, *cptr mptr = (int*)malloc(sizeof(int)); printf("%d", "mptr); cptr = (int)calloc(sizeof(int),1); printf("%d","cptr); garbage 0 000 O garbage segmentation fault Question 8 1 pts If this program "Hello" is run from the command line as "Hello 12 3" what is the output? (char '1'is ascii value 49. char '2' is ascii value 50 char'3' is ascii value 51): #include<stdio.h> int main (int argc, char*argv[]) int...
Convert this C program to Js (Java script) from Visual Studio Code #include<stdio.h> int main(){ char firstName[100]; char lastName[100]; printf("Enter Your Full Name: \n"); scanf("%s %s", firstName, lastName); printf("First Name: %s\n", firstName); printf("Last Name: %s\n", lastName); return 0; }
C program-- the output is not right please help me to correct it. #include <stdio.h> int main() { int arr[100]; int i,j,n,p,value,temp; printf("Enter the number of elements in the array: \n "); scanf("%d",&n); printf("Enter %d elements in the array: \n",n); for(i=0;i<n;i++) { printf("\nelement %d: ",i); scanf("\n%d",&arr[i]); } printf("\nEnter the value to be inserted: \n "); scanf("\n%d",&value); printf("The exist array is: \n"); for(i=0;i<n;i++) { printf("%d",arr[i]); } p=i; for(i=0;i<n;i++) if(value<arr[i] ) { p = i; break; } arr[p]=value; printf("\n"); for (i =...
what is the output of the following program? #include<stdio.h> #include<string.h> int main(void){ char word[20]; int i =0 strcpy(word, "ORGANISE"); while(word[i] !='\0'){ if(i%2 ==1) word[i] = 'C'; i++; } printf("%s",word); return 0; }
Convert the below C code to basic MIPS. Leave comments for explanation please #include <stdio.h> int main(void) { printf("Insert two numbers\n"); int a,b,c; scanf("%d",&a); scanf("%d",&b); c=a|b; printf("%d|%d=%d\n",a,b,c); return 0; }
In C Set hasDigit to true if the 3-character passCode contains a digit. 1 #include «stdio.h> 2 #include«string.h> 3 #include «stdbool.h 4 #include<ctype.h> 6 int main(void) 7 bool hasDigit; 8 char passCode501; 10 11 12 hasDigit false; scanf("%s", &passcode); 13 Your solution goes here * 14 15 if (hasDigit) 16 printf("Has a digit.n 4 #include <ctype.h> 6 int main (void) 1 8 char passCode [50]; bool hasDigit; hasDigit- false; 10 11 scanf("%s",&passcode); 12 13 14 15 if (hasDigit) 16 17...
Solve using C programming 3. lf you are given this code. #include <stdio.h> int main() int var1, var2; int sum; printf("Enter number 1:\n "); scanf("%d",&var1); printf("Enter number 2:In ); scanf("%d",&var2); sum-var1+var2; printf ("Vnsum of two entered numbers : %d", //printf ("Output: %d", res); sum); return e; Modify this code by creating a function called "addition". Make the arguments of the functions numberl and number 2. Add the two values in the function. Return a value called "result". Print "result" in...
Convert the below C code to basic MIPS. Please leave comments for explanation #include <stdio.h> int main(void) { printf("Insert two numbers\n"); int a,b; scanf("%d",&a); scanf("%d",&b); a=a<<2; b=b<<2; printf("%d&%d\n",a,b); return 0; }