Convert the below C code to basic MIPS. Leave comments for explanation please
#include <stdio.h>
int main(void)
{
printf("Insert two numbers\n");
int a,b,c;
scanf("%d",&a);
scanf("%d",&b);
c=a|b;
printf("%d|%d=%d\n",a,b,c);
return 0;
}
.data prompt: .asciiz "Insert two numbers\n" orsym: .asciiz "|" eqsym: .asciiz "=" newline:.asciiz "\n" .text # display prompt la $a0, prompt li $v0, 4 syscall # read a number li $v0, 5 syscall # store input(a) in $t0 move $t0, $v0 # read another number li $v0, 5 syscall # store input(b) in $t1 move $t1, $v0 or $t2, $t0, $t1 # c = a | b # print a move $a0, $t0 li $v0, 1 syscall # print | la $a0, orsym li $v0, 4 syscall # print b move $a0, $t1 li $v0, 1 syscall # print = la $a0, eqsym li $v0, 4 syscall # print c move $a0, $t2 li $v0, 1 syscall # print \n la $a0, newline li $v0, 4 syscall
Convert the below C code to basic MIPS. Leave comments for explanation please #include <stdio.h> int main(void) {...
Convert the below C code to basic MIPS. Please leave comments for explanation #include <stdio.h> int main(void) { printf("Insert two numbers\n"); int a,b; scanf("%d",&a); scanf("%d",&b); a=a<<2; b=b<<2; printf("%d&%d\n",a,b); return 0; }
Convert the below C code to basic MIPS. The result of this code should be a^b of the two numbers that you input. For example if you input the numbers 3 and 5 you should get a result of 3^5=6 #include int main(void) { printf("Insert two numbers\n"); int a,b,c; scanf("%d",&a); scanf("%d",&b); c=a^b; printf("%d^%d=%d\n",a,b,c); return 0; }
Fix the errors in C code #include <stdio.h> #include <stdlib.h> void insertAt(int *, int); void Delete(int *); void replaceAt(int *, int, int); int isEmpty(int *, int); int isFull(int *, int); void removeAt(int *, int); void printList(int *, int); int main() { int *a; int arraySize=0,l=0,loc=0; int choice; while(1) { printf("\n Main Menu"); printf("\n 1.Create list\n 2.Insert element at particular position\n 3.Delete list.\n4. Remove an element at given position \n 5.Replace an element at given position\n 6. Check the size of...
Solve using C programming 3. lf you are given this code. #include <stdio.h> int main() int var1, var2; int sum; printf("Enter number 1:\n "); scanf("%d",&var1); printf("Enter number 2:In ); scanf("%d",&var2); sum-var1+var2; printf ("Vnsum of two entered numbers : %d", //printf ("Output: %d", res); sum); return e; Modify this code by creating a function called "addition". Make the arguments of the functions numberl and number 2. Add the two values in the function. Return a value called "result". Print "result" in...
i need flowchart for the following c code #include <stdio.h> int main() { int n, i, sum = 0; printf("Enter an integer: "); scanf("%d",&n); i = 1; while ( i <=n ) { sum += i; ++i; } printf("Sum = %d",sum); return 0; }
Convert this C program to Js (Java script) from Visual Studio Code #include<stdio.h> int main(){ char firstName[100]; char lastName[100]; printf("Enter Your Full Name: \n"); scanf("%s %s", firstName, lastName); printf("First Name: %s\n", firstName); printf("Last Name: %s\n", lastName); return 0; }
PUT INTO PYTHON CODE #include <stdio.h> #include <float.h> int main(void) { float a = 1; float b = 0.5; float c = a + b; int bits = 0; while (c != a) { bits = bits + 1; b = b / 2; c = a + b; } printf("%d\n",bits); return 0; }
MIPS assembly language Covert this code to MIPS: #include <stdio.h> int function (int a) int main)i int x=5 ; int y: y function(x); printf "yd",y); return 0; int function (int a) return 3*a+5; Assumptions: . Place arguments in $a0-$a3 . Place return values in $vO-$v1 Return address saved automatically in $ra . lgnore the stack for this example. (Thus, the function will destroy registers used by calling function
Complete this program in C #include<stdio.h> int main(void) { int sumA(__, __); int answer; //the two parameters are start and end addresses of intA[] answer = sumA(......); printf("..........", intA); printf("The sum of integers in intA is %d.\n", answer); return 0; } //the two parameters of sumA(__, __) are start and end addresses of intA[] int sumA(..........) { ……………………. return ............. }
#include <stdio.h> #include <string.h> #include <ctype.h> #include <stdlib.h> int main(void) { /* Type your code here. */ int GetNumOfNonWSCharacters(const char usrStr[]) { int length; int i; int count = 0; char c; length=strlen(usrStr); for (i = 0; i < length; i++) { c=usrStr[i]; if ( c!=' ' ) { count++; } } return count; } int GetNumOfWords(const char usrStr[]) { int counted = 0; // result // state: const char* it = usrStr; int inword = 0; do switch(*it)...