Problem 4. (1 point) Find the solution to the linear system of differential equations 5x -8y...
Sr' = (1 point) Find the solution to the linear system of differential equations y' = (0) = 3 and y(0) = 4. -11x + 8y -12.+9y satisfying the initial conditions (t) = y(t) =
(1 point) Find the solution to the linear system of differential equations -7 + 154 - 6x +12y satisfying the initial conditions (0) - 7 and y(0) - 4. y(t)
х (1 point) Find the solution to the linear system of differential equations . 3.x + 4y satisfying the initial conditions x(0) = 2 and y(0) = 1. = =c(t) = cg(t) =
4y (1 point) Find the solution to the linear system of differential equations 6. 3. satisfying the initial conditions (0) = -9 and y(0) -7 (t) - u(t)
(1 point) Find the solution to the linear system of differential equations 192 - 60y 50 + 16y Ly' satisfying the initial conditions (0) = 10 and y(0) = -3 z(t) y(t) Note: You can earn partial credit on this problem
T (1 point) Find the solution to the linear system of differential equations 8.x - 2y 12x - 2y satisfying the initial conditions (0) = -5 and y(0) -13 z(t) = y(t) Note: You can earn partial credit on this problem. preview answers Entered Answer Preview
Find the solution to the linear system of differential equations {?′?′==−2?+12?−?+5?{x′=−2x+12yy′=−x+5y satisfying the initial conditions ?(0)=1x(0)=1 and ?(0)=0y(0)=0. د (1 point) Find the solution to the linear system of differential equations { -2x + 12y -x + 5y satisfying the initial conditions x(0) = 1 y د and y(0) = 0. x(t) = yt) =
Problem 2. S x' = 5x – 4y (8 points) Find the solution to the linear system of differential equations I y' = 2x – y satisfying the initial conditions x(0) = 3 and y(0) = 2. e(t) = g(t) = Note: You can earn partial credit on this problem. preview answers
(1 point) -1 -4 a. Given that V1 [ 2] and U2 --10 are eigenvectors of the matrix _2] determine the corresponding eigenvalues. 4 11 = 12 = = -4x b. Find the solution to the linear system of differential equations x' y' satisfying the initial conditions x(0) = -3 and y(0) = 4. 4x – 2y x(t) = y(t) =
Problem 3. (1 point) Find y as a function of tif y" + 5y - 14y = 0, y(0) = 5, y(1) = 6, y) = Remark: The initial conditions involve values at two points. Problem 4. (1 point) Find the solution to the linear system of differential equations 8x - 15y 6x-lly satisfying the initial conditions x(0) = -16 and yo) = -10 x(t) = Note: You can earn partial credit on this problem