Question

(1 point) Find the solution to the linear system of differential equations 192 - 60y 50 + 16y Ly' satisfying the initial conditions (0) = 10 and y(0) = -3 z(t) y(t) Note: You can earn partial credit on this problem

Answer 1

52 I 1 1/2 = - 19x boy de la = 5x + 1by =) dat 19x = -604 =) de lby = @+1972 Goy Q-1677 (P-16) (D+19) & -60 (D-167) 3 D +32-3042 +300x = 0 D+ 32 - 4a = => [D+4) (D-122-0 iv 52 - 300x

cat 50. x Gé t Gzet o from at 7196zet - 10 Nu ni 4E -60y = -4G teel + 199 e -96 >>-60y = 1566 + 20 ezet =) y = -qet qet Now, x(9=0 and yo)=-3 est q = 2-3= -9-4 52 frow, 39+ 4 6 = 136 3(20 (2) + 4 e 36 67 76 82 AZN => C2 = 6 So, G=4 so, algo qe att bet and ē atzet U 1) M2) - (Ans)