Question

Suppose that L = 230 mm

1) Locate the x-coordinate of the center of mass of the homogeneous block assembly.

2) Locate the y-coordinate of the center of mass of the homogeneous block assembly.

3) Locate the z-coordinate of the center of mass of the homogeneous block assembly.

250 mm L 150 mm 100 mm 150 mm 150 mm

Answer 1

Given doter :- L- 230 mm the figure Consider from question below. shown in the 2 figur mm 1 f 250 mm 230 mon 3 Isomm © atletos loo mm I somm find n Coordinale al the Conter d mass of the homogenous black assembly. 31 그 2 ngo, travetingus Σν vitu tug (75) x ( 150 X ISOX 580) x(22 225 )* (PSORIS OX 230 ) + (200)416 X 150 X 150 X100) (saxlsox Soo) + lisoyiso x 250) +1 ISOY ISO X230) + Cáx xlsoxisox loo

31 97 8750.0oot 1169975000f 225 1905 ac † 5175000+ 1125 ooo 31 122.38 mm find th ย controid of th conter of t mass of the homogeno ous block assembly. ។ E ju y vit jz Uz t ýgva Eu Vitu₂ tui 9 = (29) x (Isaxls x 500) + (50) * a + (265)x (ox IsoX 230) ISO Xiso x10.) X (ISOX Asox 500) t (Isoxlsox.230) + G* ISOX ISOX 100) y = 378 45ooooo t 290 6375 ooot 56250000 1305 oor + 5175000 t 112500D

cel = 320.2 mm find the Z- Gordinale of the center ter of mass of homogenous block body z = Ezy živit z U₂ + Zug Eu vituztus į = (75)(soy is of s80) + (75) X( ox /sox 230 (assox 150X100) (50) X + caso x iso X S80) + (Isot psoX220) + X 150 X 150 X 100) 2 NI 97875 0000 + 388125 000 + 5625 000 17050000f 5175000+ 1125 ooo = IN 70 g mom