Question

5. Machine Element For the machine element shown, locate the x coordinate of the center of gravity. 54 mm 120 111n X = 64.2 mm Y = 19.51 mm 60 mm 40 mm r = 16 WEET 27 mm IS mm .

Answer 1

* This many made with Machine Element is Standard Shapes 1 Bottom cuboid 2) Prism (slop part) 3) semi circular disc 4 cylindrical hole we will 4 parts respeer Calculate the Ар (аммо 4 of this & Their x-co-ordinate with to 444, 2 (co-ordinate system) Bo Hom cruboid y 218 mm Width is = 54 mm 120+40=160mm = 160818854 Nolume ) vi V= 155520 mm *4=80 my * - Cordinate of shape hape) II - 160 80 mm 2 prism (slop part) 2) 42 V2 42x120x54 2 Bu 120 54 V = 136080 mm 3 X2 120 3 Аб мм h = 40mm

semi circular disc 2. D V₂ = Arth Z 2 7 x 2 V3= 20612 mm м2 ₂ = 160+ 4R - 160+ 4x27 371 3T X = 160+ 11.46 olz=171.46 mm 24 cylindrical hole V4 = 78²h - (0)2x15 V = 14476.46 mm 3 This is a hole 50 Volume is -ve X = 120 + 40 Xu= 160mm

# x coordinate of the centre of gravity Vy az a = V, ou + V2 X2 + V₂ *z V, + V2 +₂ - Vy À = (155520880)+(1360608 40)+(171.46 * 2005 – (14476.407 1007 ISS520t 136080 + 20612 14476046 64.16 mm Ans

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