Question

correct answer is : Max stress:40.24mpa, min stress =0

Part II: Problem 7 (15 points) Determine the maximum bending stress and its location on the beam if M = 50 kN-m. What is the minimum stress and where is it located? 200 mm 20 mm 300 mm M 20 mm 20 mm

Answer 1

200 50 Knim M et conter = --20 ..Az M 300 mm Neutral aus A3 260 mm Location Ý ZOM A, } , f Az Y + AZ - 130 Apt A 2f Az JSD mm. 140 20 200 200*20) X10 +(200 xrd) x 290 +260 x 20)* 150 + = 150 mm. (260*20) + 2x 200 x 20) as there is symm lies symenty We it also N-A Can risuallize on c.67 So. I - 20 x 2602 + 2 2 [10053 200x20 X 1402 72008203 12 12 F 个 Art Az = [16+ Ad?] А, for Area = 150mm. I- 186-36 x 106 mm 4 I may from NA Now, may - 186.36 x 106 x 10-12 M Y 50x103 x 15 TI 40-244 x10 6. occurs at upper & Lower of Insecth ie farthest from Neutral ani's @gmax- ist negative (() and @ dower it is the (Tensile = The omax At upper it

The minim stress lies at Neutral Ares where and its is Omin =0 and value į = 0. N, A.

Using the bending equation. maximum bending stress occurs at Ymax from neutral axis and minimum occurs at NA ie Equal to zero.