Question

A particular material has a workfunction of (15.2 + A)/10 eV. Find the maximum wavelength of electromagnetic radiation that will result in the emission of photoelectrons from this surface. Give your answer in nanometers (nm) and with 3 significant figures.

A: 6

An electron is accelerated from rest by a potential difference of (24.5 + A) V for a distance of (4.50 + B) cm. Determine the de Broglie wavelength of the electron. Give your answer in picometers (pm) and with 3 significant figures.

A: 6

B: 4

Imagine the energy levels in an atom are given by E_n = - (8.30+A)eV/n². Find the wavelength of the photon emitted when an electron goes from n = (2+B) to n = 1. Give your answer in nanometers (nm) and with 3 significant figures.

A: 1

B: 4

Answer 1

Here ev -- where A = . work function q - 15:244)/10 ] p - (15:2.46 Jev: 2.12% wavelength of the electronghetie radiatiny then P ev If is the ht o he 77 V o m 6.62x10²4 X 3x108 2:12 X 1.6 x to! 5.185 x 1024 = 585 now my X

CIV = (24.5+4 5+A) V 30-50 b> Potential difference Where À = 6: them 4V = (24.5+6) It wo is the velocity of electron 'ther u 29 av x 10 -19 C 4 :> change of electron =16* m-> mass of electron 9:11 X10 obliky 2x1.6x1079 x 30.5 9.11 X.10-31 m/s وا √107x10² m/s 3.22 x 100 m/s thesion de Broglie Guare length mer -0% a .6.63*10:34 m 9.11 X10-31 x 3.27 x 106 = 0.222x 109 222 pm > En where A=1 toi V pl 34 2.2009 Dar 26 senten) evi ņ = (2+0) = (2+4)=6 En to n = I 9:31. اور ci movie eva -0.26. v 6ř En 9.3 ev 7- 9.3 ev En Change of energy AE & En 340:26 +9.3) ev = 9.048 If it is the Gwavelength of emitted Photon then 2

뜻 645x100m AES he 9 0 he ovew 9. 00 x 10-19 1. 38 x 10a (1. 138 nr 시