An electron is accelerated from rest by a potential difference of 38.5 V for a distance...

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An electron is accelerated from rest by a potential difference of 38.5 V for a distance...

An electron is accelerated from rest by a potential difference of 38.5 V for a distance of 11.5 cm. Determine the de Broglie wavelength of the electron. Give your answer in picometers (pm) and with 3 significant figures.

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Answer 1

Answer #1

Using law of conservation of energy,

0.5 mv^2 = qV

0.5 x 9.1 x 10^-31 v^2 = 1.6 x 10^-19 x 38.5

Velocity, v = 3.68 x 10^6 m/s

Wavelength, lambda = h/mv

Lambda = (6.63 x 10^-34)/(9.1 x 10^-31 x 3.68 x 10^6)

Lambda = 198 pm

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Answer 2

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