Question

Part A If the velocity of a pitched ball has a magnitude of 43.5 m/s and the batted ball's velocity is 60.0 m/s in the opposite direction, find the magnitude of the change in momentum of the ball and of the impulse applied to it by the bat. Express your answer to three significant figures and include the appropriate units.

Constants Force of a Baseball Swing. A baseball has mass 0.137 kg - Part A If the velocity of a pitched ball has a magnitude of 43.5 m/s and the batted ball's velocity is 60.0 m/s in the opposite direction, find the magnitude of the change in momentum of the ball and of the impulse applied to it by the bat. Express your answer to three significant figures and include the appropriate units. emplates Templates ymbole undo redo reset keyboard shortcuts help P= Value Units Submit Request Answer - Part B If the ball remains in contact with the bat for 1.9 ms , find the magnitude of the average force applied by the bat. Express your answer to two significant figures and include the appropriate units. Templates Symbols undo redo reset keyboard shortcuts help Value Units Submit Request Answer < Return to Assignment Pravide Feedback

Answer 1

Impulse momentum equation Impulsa change in momentum flow change initial velocity u= 43.5u/ P in momentum = mv- mu (U-) P = 0.1576-60-43.5) final veloites VE - Gomis tu= 0.137kg P = -14.1795 kg nys P = 14.1795 kg m/s magnitude from ea Impulle = 14.1795 kg, nys = Fit t=1.943 Impulse Impulse Inpu F=7462.89 N 14, 1795 1.9x103 = 1.9x10ls