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Calculate the boiling point of a 3.60 m aqueous sucrose solution. Express your answer in degrees Celsius to five significant
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Answer #1

Kb for water is 0.512 oC/m
calculate ΔTb
ΔTb = Kb*m
= 0.512*3.6
= 1.8432 oC

This is increase in boiling point
boiling point of pure liquid = 100.0 oC
So, new boiling point = 100 + 1.8432
= 101.8432 oC
Answer: 101.84 oC

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