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Mass of KyFe(C204)y. ZH20 : 4.60 g Mass of sample : 0.195 g Mass of FeCl3 used in preparation : 1.60 g Molarity of standard N

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  • Calculate the mass of potassium in the sample :

    1st equivalence point corresponds to K+ ;

    mol K+ = moles of NaOH used in titration (from V1 ) = 0.100 mol/L * 6.00 ml/1000 ml/L = 0.00060 moles

    mass of K+ in sample =  0.00060 moles* 39.1 g/mol = 0.02346 g

    Calculate the percent of potassium in the sample :

    mass of K+ in sample / mass of sample *100

    0.02436 g / 0.195 g *100 = 12.03 %

    Calculate the volume of standard NaOH that reacted with iron :

    V2 -V1 = 16.40 ml - 6.00 ml = 10.40 mL

    Calculate the mass of iron in the sample :

    three moles of hydroxide ion are required to react with each mole of iron ion in the salt.

    moles of Fe = 1/3* moles of NaOH used in titration (form V2 - V1) = 0.100 mol/L * 10.4 ml/1000 ml/L /3 = 0.000347 moles

    mass of Fe in sample = (moles of Fe)(55.85 grams/mole) = 0.000347 moles*55.85 g/mol = 0.01936 g

    Calculate the percent of iron in the sample :

    mass of Fe in sample / mass of sample *100

    0.01936 g / 0.195 g *100 = 9.93 %

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