Question

DESCRIPTION: The total pressure of a flow decreases along a streamline due to losses associated with non-ideal affects. These losses can be broken into major and minor total pressure losses. In this experiment, the major and minor total pressure losses through a pipe outfitted with a gate valve will be determined using pressure taps drilled into the pipe surface. The total pressure losses will be used to calculate the flow's friction factor and the valve's loss coefficient for a variety of flow rates and valve positions. Figure 1 is a diagram of the pipe configuration used in the experiment with labeled geometric parameters. P: P2 P3 Par| Paitta L. L3 Figure 1: Schematic of a pipe flow setup with relevant dimensions labeled. Water with a flow rate will be supplied to the system by a pump and recorded using a flowmeter attached upstream of the system. Pressure transducers attached to the pressure taps will record the static pressure difference Paiff.1 between Position 1 and Position 2 and the static pressure difference Parf.2 between Position 2 and Position 3. Known Parameters: The following information is known about the system: L : 24.25 in L2:25.25 in D: 0.302 in €: 0.00108 in

Answer 1

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solution - These are vorious methods and send formula for calculating the friction factor. There are two flows ie a) Lammas flow b) Turbellant flow - Lammar flow in pipes then we call it as laminar flow. Re < 2000 Re > Re PVD u → Darocy weisback equation he fl v² losses due to friction 282 Herre, f = 64 P = deroity of flaid V = Velocity =) Turbulent flow u = dynomic viscosity U= 2.5 y my to 3 logerithmic dustoi bution of veloce If K cecs' => Hy drodynamic smooth pipe K »S' = Hydrro dynamic rough pipe Now

K = Average height of roughmels Si= Height of lominos subkyer s = 11.68 ng - kimematic viscosity v* v* V P Now Nikuvad se's condition <0.25 5 smooth K S ķ k S & transition 0.25 L Rough 4 к 6 Reynold's condition <4 smooth K V*k < 100 a transition < 14 > Rough 100 < v*k oo for rough pipe 2 lagi ( 2 ) + 1.74 for smooth Pipe f = 0.316 0.316 for 3x10 3 < Re < 100 x0² Rel14 (Re) 0.25