Question



A 71 kg trampoline artist jumps vertically upward from the top of a platform with a speed of 4.8 m/s. (Figure 1)
Part B If the trampoline behaves like a spring of spring constant 5.5*104 N/m, what is the distance he depress it? Express yo
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Answer #1

The kinetic energy and potential energy of the artist will be changed into spring potential energy

0.5mv^2+mgx = 0.5kx^2
solving for x we get

X = 0.185m

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