Question

A spring has k = 71 N/m Pro Type here to search II

Answer 1

Work done,

$W(x )= \frac{1}{2}kx^2$

Work done from x1 to x2 is : $W = \frac{1}{2}k(x_2^2 - x_1^2)$

Work done from 3.2 cm to 7.7 cm is : $W = \frac{1}{2}*71*(0.077^2 - 0.032^2) = 0.17 J \rightarrow Answer$

5 F (N) 0 3.2 7.7 X ( cm )