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17. Probability of More Than 36 Girls Assuming that boys and girls are equally likely, estimate the probability of getting mo
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Answer #1

Let, X_{i}=I(The\;i-th\; born\; is\; a\; girl) for i \in \{1,2,\cdots,64\}

Note that X_{i} follows Bernoulli (0.5) distribution independently and identically. (Since girls and boys are equally likely.)..............(1)

So, T=\sum_{i=1}^{64}X_{i} is the number of girl childern.

So, T~ Binomial(64,0.5) (by (1))

So, P(more than 36 girls in 64 births)=P(T>36)=1-P(T less than equal to 36)=1-0.8697=0.1303 (Calculation done in R software using the command pbinom(36,64,0.5)).

There is only 14% chance of getting more than 36 girl children in 64 births.

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