Question

unit 3 topic 12 excercise 12-14

C2- + en.wileyplus.com/edagen Rossman, Workshop Statistics Discovery with Datate As Gradebook Unit Topic 12. Exercise 12-14 Dog Heights Suppose that heights of male German Shepherds follow a normal distribution with mean 23 inches and standard deviation 2.5 heights of male Shelties follow a normal distribution with mean 16 inches and standard deviation 1.5 inches a. what percentage of male German Shepherds have a height between 20.5 and 25.5 inches? Round your answer to two decimal places. 96 b. Between what two values do roughly 95% of male Sheltie's heights fall? Enter your answers in increasing order inches. inches and About 95% of all male Sheltie's heights fall between C. How tall must a male Sheltie be to be among the tallest 10% of Shelties? Round your answer to two decimal places inches 2000-2020 John Wile Sons, Inc. All Rights Reserved. A Division of only one

Answer 1

Z-score x - 26 (German toe X-ul shepheeds) Z-score = 26-23 2-5 - - 2-03 Prob = P( Zc-2.03) = 0.0211 z score for y= 19 2-suose - Y-4 19-16 = 2 1.5 heigh :P(272) = 0.0228 The poob. that male G.S. having a of goeter than 26 inches i's 0.9789 male shelfie height greter than ig iches is 0.9772 => Therefore, male German she is more unsual. pob that howing

page-2 b find 95 J. (middle) values P (Y<y) = 0.025 Z-score -1.9600 Y-16 -1.9600 - Y = 16- (1.988 1.5 TY 13.060) Now Percy)= 0.975 Y-16 1.96 1.5 Y = 18.9399 .. About 95% of all male height fall bet 13.07 inches 18.94 inches male shelties to To find PlYcy) = 0.9 Y-16 - 1.2816 1.5 Y = 17.9223 Toll height (7.93 inches

page-1 x is ev. of height of male German Shepherds XN NCM, 6) l, mean = 23 inches = 2.5 inches Y is ev. of height of male shelties 1643) My - mean = 16 inches by inches @ P (20.5 < x < 255) 20.5-23 25.5 - 23 X-ul < YN N (oldy 1.5 2.5 2.5 -) <251) = P(2¢1)-P(24-1) - = 0.8913 -0.1587 0.6827 :.P(-15241)=P(28.5{XZ 25. 25.5) = 0.6827 percentage is 68.27 %