Question

I get questions a and be but don't understand how they got the answers for c, d and e. Please explain
The heights of adult men in a certain country are normally distributed with a mean of 69.1 inches and a standard deviation of 2.6 inches. Complete parts (a) through (e) below. a. What are the standard score and percentile of a height of 74 inches? The standard score is z= 1.88. (Round to two decimal places as needed.) The percentile is the 96.99 percentile. (Round to two decimal places as needed.) b. What are the standard score and percentile of a height of 65 inches? The standard score is z= - 1.58. (Round to two decimal places as needed.) The percentile is the 5.7 percentile. (Round to two decimal places as needed.)

Answer 1

© I foot = 12 inch s'," = (5x12 +11) inch inch z = 71-69.1 2.6 0.73 P(x>5'0") = P12 70-73) = 1-0.7673 [from Z-score table = 23:27 % Answer s'8" = (5x 12 +8)" = 68" d z = 0.423 68-69.b 2.6 [from Z-score P(x2 s'p") = P(Z <-D-423) = -3372 table] -33-721. ZGe 6/6:"= 6x12 +6"= 78" Z= 78-69.1 - 3.423 .2.6 3") X10-4 Plz>3,423) =lMo99969 = 301 x 10 total men in 10 million = 3:1810-4x10x106 Aus 3100 cs Scanned with CamScanher