A small insect is placed 6.50 cm from a 7.00-cm-focal-length lens. Calculate the angular magnification. Express your answer using two significant figures.
A small insect is placed 6.50 cm from a 7.00-cm-focal-length lens. Calculate the angular magnification. Express...
calculate the angular magnification (*note i already posted this question once and the answer is not 14) the distance of the image from the previous problem is -91cm if that helps. = PHYS102 Summer 2020 <Ch 25 HW Problem 25.26 A small insect is placed 6.50 cm from a 7.00-cm-focal length lens. ✓ Correct Part B Calculate the angular magnification Express your answer using two significant figures. ΨΗ ΑΣΦ 6 * Ο ? M= 14 Submit Previous Answers Request Answer...
A small insect is placed 5.50 cm from a 6.00-cm-focal-length lens. a) Calculate the position of the image. Follow the sign conventions. Express your answer using two significant figures and include appropriate units. b) Calculate the angular magnification. Express your answer using two significant figures.
A small insect is placed 4.35 cm from a 5.00-cm-focal-length lens. A) Calculate the position of the image. Follow the sign conventions. Express your answer using two significant figures and include the appropriate units. B) Calculate the angular magnification. Express your answer using two significant figures.
A small insect is placed 5.45 cm from a 6.00-cm-focal-length lens. Part A Calculate the position of the image. Follow the sign conventions. Part B Calculate the angular magnification.
(4) When an object is placed at a distance of 8 cm from a lens, the magnification is -5. (a) What is the focal length of the lens? (b) If the object is placed at 10 cm from the same lens, what is the magnification of the image? <Real Virtual> (c) Characterize the image formed in (b) by I <no image forms> <Upright:Inverted> <Enlarged: Unmagnified:Reduced> 1 and tell why
The focal length of a lens is 4.5 cm. Calculate the maximum angular magnification of a simple magnifier when the image is formed at the normal near point of the eye.
The focal length of a lens is 4.6 cm. Calculate the maximum angular magnification of a simple magnifier when the image is formed at the normal near point of the eye.
A microscope has an objective lens with a focal length of 10.0 mm . A small object is placed 0.90 mm beyond the focal point of the objective lens. If an eyepiece with a focal length of 2.5 cm is used, with a final image at infinity, what will be the overall angular magnification of the object? Express your answer using two significant figures.
A converging lens with a focal length of 40 cm and a diverging lens with a focal length of -40 cmare 150 cmapart. A 1.0-cm-tall object is 60 cmin front of the converging lens. Ch 19 HW Problem 19.41 8 of 8 Part A Calculate the image position Express your answer using two significant figures. Constants A converging lens with a focal length of 40 cm and a diverging lens with a focal length of -40 cm are 150 cm...
Problem 27.28 2 of 3 n Review A converging lens of focal length 8.15 cm is 17.0 cm to the left of a diverging lens of focal length -7.00 cm . A coin is placed 12.0 cm to the left of the converging lens. Part A Find the location of the coin's final image, measured from the diverging lens (positive if to the right or negative if to the left). Express your answer using three significant figures. VAZO ? cm...