Question

Problem 27.28 2 of 3 n Review A converging lens of focal length 8.15 cm is 17.0 cm to the left of a diverging lens of focal length -7.00 cm . A coin is placed 12.0 cm to the left of the converging lens. Part A Find the location of the coin's final image, measured from the diverging lens (positive if to the right or negative if to the left). Express your answer using three significant figures. VAZO ? cm Submit Request Answer Part B Find the magnification of the coin's final image. Express your answer using two significant figures. VOAO ? m =

Answer 1

f = 8.15cm, fa=-7cm, D=17cm do =+12cm. dif=? f if v di dogs a Kdo

for converging lens att ㅗ where do=12cm, fc=8.15cm. fc di do ㅗ =

I di 8.15 12 di = 25.40cm this image will be object for diverging lens dor=17-25.40=-8.400m, fd = , fd =-7cm. Itt d die dog - dif -7 8.40 lens dip= -42cm.] left of the diverging B) het magnification mace e dit = (-25.4) (+220) dot m=

m=10.58