Question

A converging lens of focal length 9.000 сm is 20.0 cm to the left of a diverging lens of focal length -6.00 cm. A coin is placed 19.0 cm to the right of the diverging lens. Part A Find the location of the coin's final image. to the left of the converging lens between the lenses to the right of the diverging lens Submit Previous Answers ✓ Correct
A converging lens of focal length 9.000 cmcm is 20.0 cmcm to the left of a diverging lens of focal length -6.00 cmcm. A coin is placed 19.0 cmcm to the right of the diverging lens.

Answer 1

Solution in the uploaded images

Solution fdem ty = – blon tve ve H 20cm 18cm liverging lens: For for fiz-ben tou= - 19h job- d 1 8.77cm ce u= 20- To the right of diverging lens, For converging lens, 8.77= - 28.77 cm using leas formula 4-5 to the light of converginglens) Image distance, di- 13.1 cm to the converging - 28.77 Image, I = 13.1cm (to the Part B: left of less.

Ppart a From above m, & -8.77 -19 = 0.46 me=w 13.1 - 28.77 -0.455 Total magnification mana m, xm, 0.46x -0.455 elm = -0.209 Hit like, Finel image is invested and diminished!