Question

Check the two-way shear action (punching shear) around an interior column (500x500mm) of flat plate slab (8x8m).
Assume,
Slab thickness = 200 mm,
d = 180 mm
Wu = 16 kN/m² ,
fc' = 25 Mpa,
fy = 400 Mpa
spacing between stirrups s = 90 mm

Answer 1

here vf is greater than vc so it is not adequate for two way shear

63.5376 m2. SON Guven interior column = 500x500mm Slab thickners = 200min. Wu= 16 kw/m" & mx 8m flat plate fc' = 25mpa. fy = 40ompa. Spacing blw Stirrupss=90mm um -am 10/27 4 m 8m bo= perimeta of critical regions 8 88 (800+180)x2+(508tiec? 2520 mm - A Area of tributary oregion = 64- (60-57018)x Caschi 64-668866) 64-(0.4624) .-4 Shear force Y = Wuxa 16x 63.5376 lol660 1017 KN. l ve shear stress (vf) factoved Vs. bood 1017 103 2120x180 0.1976c rfi (! + Vc 2.07 MPa for checking theor two way a e must av :: vf <ve (factored shea neristance of concrete) '2_) due to min BL Theses (la ) +0.14] ad pia 0-25 rec Be = longer side of coluna/ shortensas soon O 0.19 (1)(0.9) 125 ( 1 2.56mpa 4 for interior column 3 for edge column 2 fa quarta column ( lt 4x180 + 0.19 on)](/(0.4) (1)(0.9) 15 2720 2.04 mpa 3 0.25 Tiit 0.28 Tas- 2 1.25mpa Here 10 went is 1.25mpa !! - Vc = 1.25mp vf we get = 2.07mpa Here 1.25 mpa Hae 2.07mpa > c = 1.25mpa This is not adequate for 2-way shear Scanned with CamScanner Scanned with CamScanner